9x^2-1020x+12000=0

Solution for 9x^2-1020x+12000=0 equation:

9x^2-1020x+12000=0

a = 9; b = -1020; c = +12000;
Δ = b2-4ac
Δ = -10202-4·9·12000
Δ = 608400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{608400}=780$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1020)-780}{2*9}=\frac{240}{18}
=13+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1020)+780}{2*9}=\frac{1800}{18}
=100
$